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Grade 11 Physics

Grade 11 Physics on Temari has 11 revision cards, arranged by the chapters of the Ethiopian national curriculum. Every card says when the rule applies, what each symbol in it stands for, and the mistake students most often make with it. They are free to read and need no account.

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6 September 2026
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Across the whole subject

What is comparedHeatTemperature
What it isEnergy that moves from a hotter body to a colder one.The degree of hotness or coldness of a body.
Where it livesNowhere. A body stores internal energy, and heat is the name for that energy only while it crosses a boundary.In the body itself, as a property you can read at any moment.
SI unitJoule (J). Also the calorie, where 1 cal is about 4.186 J.Kelvin (K). Also degrees Celsius and degrees Fahrenheit.
Does the amount matterYes. Heating more mass takes more heat, so a pot of boiling water needed far more than a cup.No. The cup and the pot both sit at 100 °C.
What it depends onThe mass, the specific heat capacity of the substance, and the temperature change.The average translational kinetic energy of one particle, not the total for the whole sample.
How you measure itIndirectly, with a calorimeter, from measured temperature changes and known specific heat capacities.Directly, with a thermometer.
What zero meansNo net heat crosses between two bodies that are already at the same temperature.0 K is absolute zero and has never been reached, and kelvin values are never negative. 0 °C is an ordinary temperature, the freezing point of water.
The formulaQ=mcΔTQ = mc\,\Delta T while the temperature changes, Q=mLQ = mL while the substance changes state.Read off the scale. A change of 1 °C is the same size as a change of 1 K.

When you use it

Reach for this when a question treats heat and temperature as one word: how much energy warms a mass of water, why the reading stops climbing while ice melts, or why two bodies stop exchanging energy once they are equally hot.

Watch out

Two mistakes cost marks here. The first is using Q=mcΔTQ = mc\,\Delta T while ice is melting or water is boiling. The temperature stays put during a change of state, so ΔT\Delta T is zero and the formula returns zero heat. The right one is Q=mLQ = mL, and warming ice at -10 °C into steam is several separate steps rather than one. The second is turning a temperature CHANGE into kelvin by adding 273. Water warmed from 20 °C to 70 °C has changed by 50, in °C and in K alike. Add 273 to a temperature, never to a difference.

What is comparedConductionConvection
What it isHeat moving through a material while the material itself stays where it is.Heat carried by the bulk movement of a fluid.
Where it worksIn solids, liquids and gases.In liquids and gases only, because only a fluid can flow.
How the energy travelsFrom particle to particle by vibration and collision. In a metal, free electrons carry most of it, which is why metals beat wood and water.The hot fluid itself moves and takes the energy with it, so warm fluid rises and cool fluid sinks. Natural convection is driven by the density difference heating creates, forced convection by a fan or a pump.
Rate lawFourier's law: Qt=kAΔTL\dfrac{Q}{t} = kA\dfrac{\Delta T}{L}, where L is the thickness measured along the direction of flow.Newton's law of cooling: Qt=hA(TsTf)\dfrac{Q}{t} = hA(T_s - T_f), where TsT_s is the surface temperature and TfT_f that of the bulk fluid.
Unit of the coefficientk is in W m1K1\text{W m}^{-1}\text{K}^{-1}, because the conduction law divides by the thickness L.h is in W m2K1\text{W m}^{-2}\text{K}^{-1}. There is no L anywhere in the convection law.
Which is fasterInside one fluid it is the slower of the two. Along a copper bar it beats convection in still air easily, so this is not a universal rule.Inside one liquid or gas it normally moves heat faster, because the material carries the energy with it.
Across a vacuumIt cannot cross one. Conduction needs matter.It cannot cross one either. Only radiation crosses empty space.
Everyday examplesA metal spoon warming in hot tea, the base of a cooking pan, the fins of a heat sink.Water circulating in a boiling pot, land and sea breezes, warm air rising in a room.

When you use it

Use when a question asks how heat gets from one place to another and you have to name the mode, or when you have to put a number on it with Fourier's law or Newton's law of cooling. The medium decides: a solid can only conduct, while a liquid or a gas does both.

Watch out

Two mistakes cost a mark. The first is copying k's unit onto h and writing the convective coefficient as W m1K1\text{W m}^{-1}\text{K}^{-1}. Divide the law out instead of memorising it: h=Q/tAΔTh = \dfrac{Q/t}{A\,\Delta T}, which is W m2K1\text{W m}^{-2}\text{K}^{-1}. k keeps the extra metre only because the conduction law divides by the thickness L, and there is no L in the convection law at all. The second is answering that conduction works in a vacuum because two solids can touch. It does not. Both modes need matter, and radiation is the only one that crosses empty space, which is why a vacuum flask still loses heat and why the Sun reaches us at all.

What is comparedInertiaMomentum
What it isThe property by which a body resists any change in its state of rest, or of uniform motion in a straight line.The quantity of motion a body has because of its mass and its velocity.
Whose it isA property of the body itself, and mass is the measure of it.A quantity the body has only while it is moving.
When it is thereAlways, at rest and in motion alike.Zero for a body at rest in the frame you are working in, and there as soon as the body moves in that frame.
How it is measuredBy mass, so inertia is proportional to m. Mass is a scalar, in kilograms.p=mvp = mv, in kg m s1\text{kg m s}^{-1}. That is the same unit as the newton second, since 1N=1kg m s21\,\text{N} = 1\,\text{kg m s}^{-2}.
DimensionMass, the measure of inertia, carries [M][M].[MLT1][M L T^{-1}], mass times velocity.
DirectionIt has none. Mass is a scalar.It is a vector, pointing along the velocity.
What it depends onIn straight line motion, on the mass alone.On the mass and the velocity together, so a light bullet can carry as much as a heavy body moving slowly.
How it changesOnly if the mass changes, as it does for a rocket burning fuel.Whenever a net external force acts, and the change equals the impulse of that force.
Everyday examplesA standing passenger falls backwards when the bus starts and forwards when it brakes. Dust leaves a beaten carpet because the dust stays behind.A moving car, a kicked football and a fired bullet all carry it.

When you use it

Use when a question puts the two words in one sentence: why a parked lorry is hard to push, why a passenger lurches when a bus starts, or what a moving body hands over in a collision. The inertia compared here is the straight line kind, measured by mass, which is a different quantity from the moment of inertia a turning body has.

Watch out

Students hear that a heavy lorry has huge inertia and write that a parked lorry has huge momentum. A body sitting still has all of its inertia and exactly zero momentum, because p=mvp = mv and v is zero. The same confusion turns the bus the wrong way round: when the bus starts your body stays at rest and you fall backwards, and you are thrown forwards only when it brakes. Check the velocity before you claim momentum, and ask which way the vehicle is changing speed before you say which way the passenger falls.

EquationThe quantity it leaves outReach for it when
v=u+atv = u + atssno distance is given or wanted
s=ut+12at2s = ut + \tfrac{1}{2}at^{2}vvthe final velocity is unknown
v2=u2+2asv^{2} = u^{2} + 2asttno time is given or wanted
s=(u+v2)ts = \left(\dfrac{u+v}{2}\right)taathe acceleration is unknown

When you use it

Use for any body moving in a straight line with constant acceleration. List what the question gives you, spot the quantity it never mentions, and take the equation that leaves that quantity out.

Watch out

All four hold only while the acceleration stays constant. A body on a curve, or one whose acceleration changes, needs calculus instead. Take displacement, velocity and acceleration as positive in one direction and negative in the other, or a body thrown upwards gives an answer with the wrong sign.

What you are findingFormulaConditions it holds under
Net force on a massFnet=maF_{net} = mamass constant, FF the resultant
Force from momentumFnet=ΔpΔtF_{net} = \dfrac{\Delta p}{\Delta t}holds even when mass changes
Action and reactionF12=F21F_{12} = -F_{21}always, on two different bodies
Linear momentump=mvp = mva vector, along the velocity
ImpulseJ=FΔt=ΔpJ = F\,\Delta t = \Delta pconstant force over Δt\Delta t
WeightW=mgW = mggg is local, not a constant of nature

When you use it

Use when a question asks what a force does to a body: how fast it speeds up, how hard two bodies push on each other, or what a collision leaves behind. Momentum is conserved in every collision; kinetic energy is conserved only in an elastic one.

Watch out

The two forces of the third law act on two different bodies, so they never cancel each other out. Students subtract them from one another and get zero acceleration for a book resting on a table, when the pair that actually balances is the table's push and the Earth's pull, both acting on the book.

What you are findingFormulaConditions it holds under
Work by a constant forceW=FscosθW = Fs\cos\thetaθ\theta between force and displacement
Kinetic energyKE=12mv2KE = \tfrac{1}{2}mv^{2}speeds well below light speed
Gravitational potential energyPE=mghPE = mghnear the ground, gg uniform
Work and energy theoremWnet=ΔKEW_{net} = \Delta KEalways, for any net force
Average powerP=WtP = \dfrac{W}{t}work done over a whole interval
Instantaneous powerP=FvcosθP = Fv\cos\thetaat one moment
Efficiencyη=useful outputtotal input\eta = \dfrac{\text{useful output}}{\text{total input}}never greater than 1

When you use it

Use when a question gives you distances and speeds but no time, or asks how much fuel, food or electricity a job costs. The work and energy theorem is often a shortcut past the equations of motion, because it never asks how long anything took.

Watch out

A force at right angles to the motion does no work at all, so the tension in a string swinging a stone in a circle adds no energy however fast it goes. The cosine is what carries this, and dropping it is the commonest lost mark in the topic.

Straight lineTurningWhat changes
ssθ\thetametres become radians
v=stv = \dfrac{s}{t}ω=θt\omega = \dfrac{\theta}{t}v=rωv = r\omega
aaα\alphaa=rαa = r\alpha
mmI=mr2I = \sum mr^{2}mass becomes moment of inertia
F=maF = maτ=Iα\tau = I\alphaforce becomes torque
p=mvp = mvL=IωL = I\omegamomentum becomes angular momentum
KE=12mv2KE = \tfrac{1}{2}mv^{2}KE=12Iω2KE = \tfrac{1}{2}I\omega^{2}the same energy, counted round an axis

When you use it

Use when a wheel, a disc or a rod turns about a fixed axis. Every equation you already know for straight line motion has a turning twin, so solve the rotating problem by writing the straight line one and swapping each quantity for its partner in this table.

Watch out

The angle must be in radians before any of the links between the two columns holds. A question given in degrees or in revolutions per minute has to be converted first, and forgetting that is what makes an answer come out a factor of 57 too large.

BodyAxisMoment of inertia
Thin rod, length LLthrough the centre, across the rod112mL2\tfrac{1}{12}mL^{2}
Thin rod, length LLthrough one end, across the rod13mL2\tfrac{1}{3}mL^{2}
Hoop or thin ring, radius rrthrough the centre, along the axismr2mr^{2}
Solid disc or cylinder, radius rrthrough the centre, along the axis12mr2\tfrac{1}{2}mr^{2}
Solid sphere, radius rrthrough a diameter25mr2\tfrac{2}{5}mr^{2}
Hollow sphere, radius rrthrough a diameter23mr2\tfrac{2}{3}mr^{2}

When you use it

Use whenever a torque question needs a number for I, or when two bodies race down a slope and you have to say which reaches the bottom first. The smaller the fraction, the closer the mass sits to the axis and the easier the body is to spin.

Watch out

Each of these belongs to one axis only. The same rod is three times harder to swing about its end than about its middle, and reading the wrong row is the usual error. For any other axis parallel to one of these, add md2md^{2}, where d is the distance between the two axes.

F=0andτ=0\sum F = 0 \quad \text{and} \quad \sum \tau = 0
F\sum F
the sum of every force on the body, taken direction by directionN\mathrm{N}
τ\sum \tau
the sum of every turning effect about any one chosen pointNm\mathrm{N\,m}

When you use it

Use for a ladder against a wall, a beam on two supports, a signboard on a bracket: anything at rest or moving steadily. Both conditions must hold at once, which is what lets you find two unknown forces from one diagram.

Watch out

The first condition alone is not enough. Two equal and opposite forces applied at different points sum to zero and still spin the body, which is why a steering wheel turns. Take moments about the point where an unknown force acts and that force drops out of the equation, leaving one unknown to solve for.

What you are findingFormulaConditions it holds under
PressureP=FAP = \dfrac{F}{A}force at right angles to the area
Pressure at a depthP=ρghP = \rho g hgauge pressure, fluid at rest
UpthrustFb=ρfgVdispF_{b} = \rho_{f}\,g\,V_{disp}ρf\rho_{f} is the FLUID's density
Flow rate stays equalA1v1=A2v2A_{1}v_{1} = A_{2}v_{2}one pipe, nothing leaking out
BernoulliP+12ρv2+ρgh=constantP + \tfrac{1}{2}\rho v^{2} + \rho g h = \text{constant}steady flow, no viscosity

When you use it

Use for anything floating, sinking, or flowing through a pipe: a dam wall, a hydraulic jack, a boat, water speeding up through a narrow section.

Watch out

The density in the upthrust equation is the fluid's, not the object's, and the volume is the volume pushed aside rather than the whole object. A block half under water displaces half its own volume. Depth pressure also depends on depth alone, so a narrow tube and a wide lake at the same depth read the same.

What you are findingFormulaConditions it holds under
Stressσ=FA\sigma = \dfrac{F}{A}force spread over the cross section
Strainϵ=ΔLL0\epsilon = \dfrac{\Delta L}{L_{0}}a ratio, so it has no unit
Young's modulusE=σϵE = \dfrac{\sigma}{\epsilon}below the elastic limit only
Extension of a wireΔL=FL0AE\Delta L = \dfrac{FL_{0}}{AE}same conditions as above
Energy storedU=12FΔLU = \tfrac{1}{2}F\,\Delta Lthe work the stretch cost

When you use it

Use when a wire, cable or beam is stretched and the question asks how far it gives, how much load it will take, or which of two materials is stiffer.

Watch out

Young's modulus belongs to the material and not to the piece: a thick steel cable and a thin steel wire share one value of E, and it is the area in the equation that makes the thick one stretch less. Past the elastic limit the ratio stops being constant and none of these rows holds any more.

The same subject in other years

An exam paper keeps asking for what the year below taught. Those cards are here too.

Questions students ask

Is there a national exam in Grade 11?
No. Ethiopia sets national exams in Grade 6, Grade 8 and Grade 12 only. These cards are for your school's own exams, and for the national exam that comes a few years later.
Where do these cards come from?
They are written against the Ministry of Education textbook for Grade 11 Physics, and every formula, constant and table row is checked again before a card goes up.
Is this free?
Yes. Every card here is free to read and the printable sheet is free to download. Neither needs an account.
When was this last checked?
6 September 2026. Cards arrive chapter by chapter, and the line under each one says when that card was last read through.

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