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Grade 9 Mathematics

Grade 9 Mathematics on Temari has 33 revision cards, arranged by the chapters of the Ethiopian national curriculum. Every card says when the rule applies, what each symbol in it stands for, and the mistake students most often make with it. They are free to read and need no account.

33
Cards
8
Chapters
18
Formulas
7
Reference tables
Grade 9 Mathematics
Textbook
Free
Price
30 August 2026
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01

The number system

n(AB)=n(A)+n(B)n(AB)n(A \cup B) = n(A) + n(B) - n(A \cap B)
n(AB)n(A \cup B)
number of elements in the union of A and B11
n(A)n(A)
number of elements in set A11
n(B)n(B)
number of elements in set B11
n(AB)n(A \cap B)
number of elements in the intersection of A and B11

When you use it

Use when solving word problems or calculating the number of elements in overlapping sets.

Watch out

Remember to subtract the intersection n(A and B), otherwise shared elements will be counted twice.

Drafted from Grade 9 Mathematics, pages 1-86, then checked twice before it went up

a=bq+r(0r<b)a = bq + r \quad (0 \le r < b)
aa
dividend11
bb
divisor11
qq
quotient11
rr
remainder11

When you use it

Use when finding the unique quotient and remainder of positive integers, or when expressing division relations.

Watch out

The remainder r must always satisfy 0 <= r < b. It can never be negative or greater than or equal to the divisor.

Drafted from Grade 9 Mathematics, pages 1-86, then checked twice before it went up

Set TypeFormula for n ElementsExample for n = 3
All Subsets2n2^n23=82^3 = 8
Proper Subsets2n12^n - 1231=72^3 - 1 = 7

When you use it

Use to quickly find the total number of subsets or proper subsets for any finite set.

Watch out

A set is never a proper subset of itself, which is why proper subsets have 1 subtracted from the total.

Drafted from Grade 9 Mathematics, pages 1-86, then checked twice before it went up

GCF(a,b)×LCM(a,b)=a×b\text{GCF}(a, b) \times \text{LCM}(a, b) = a \times b
aa
first natural number11
bb
second natural number11
GCF(a,b)\text{GCF}(a, b)
Greatest Common Factor of a and b11
LCM(a,b)\text{LCM}(a, b)
Least Common Multiple of a and b11

When you use it

Use when finding the LCM or GCF of two numbers given their product and one of the values.

Watch out

This product formula holds only for two numbers. It is not true for three or more numbers.

Drafted from Grade 9 Mathematics, pages 1-86, then checked twice before it went up

a2b=ab(a>0,b>0)\sqrt{a^2 b} = a\sqrt{b} \quad (a > 0, b > 0)
aa
rational factor taken out of radical11
bb
remaining radicand11

When you use it

Use when simplifying square roots or combining like irrational terms in addition and subtraction.

Watch out

Square roots can only be combined by addition if they have identical radicands, so simplify each term first.

Drafted from Grade 9 Mathematics, pages 1-86, then checked twice before it went up

02

Solving equations

When you use it

Use when solving an equation where an algebraic expression is enclosed inside absolute value bars.

Watch out

If the isolated absolute value equals a negative number, the equation has no solution immediately.

Drafted from Grade 9 Mathematics, pages 87-129, then checked twice before it went up

Discriminant ValueNature of RootsNumber of Real Roots
D=b24ac>0D = b^2 - 4ac > 0Real and distinct22
D=b24ac=0D = b^2 - 4ac = 0Real and equal11
D=b24ac<0D = b^2 - 4ac < 0No real roots00

When you use it

Use to determine the number and type of roots of a quadratic equation without solving it completely.

Watch out

A negative discriminant means there are no real roots. Do not take the square root of a negative number in real numbers.

Drafted from Grade 9 Mathematics, pages 87-129, then checked twice before it went up

When you use it

Use when solving equations containing variables under square roots or fractional exponents.

Watch out

Squaring both sides can introduce extraneous solutions. You must check every candidate root in the original equation.

Drafted from Grade 9 Mathematics, pages 87-129, then checked twice before it went up

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
xx
roots of the quadratic equationnonenone
aa
leading coefficient where a is not zerononenone
bb
coefficient of the middle termnonenone
cc
constant termnonenone

When you use it

Use to find the solutions of any quadratic equation in the standard form ax^2 + bx + c = 0.

Watch out

The division by 2a applies to the entire numerator including -b, not just the square root part.

Drafted from Grade 9 Mathematics, pages 87-129, then checked twice before it went up

Ratio ConditionSystem ClassificationNumber of SolutionsGeometric Lines
a1a2\frac{a_1}{a_2} is not equal to b1b2\frac{b_1}{b_2}IndependentOne unique solutionIntersecting
a1a2=b1b2=c1c2\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}DependentInfinitely manyCoincident
a1a2=b1b2\frac{a_1}{a_2} = \frac{b_1}{b_2} is not equal to c1c2\frac{c_1}{c_2}InconsistentNo solutionParallel

When you use it

Use to classify a two-variable linear system as independent, dependent, or inconsistent using coefficient ratios.

Watch out

Make sure equations are aligned in the same standard form before comparing coefficients.

Drafted from Grade 9 Mathematics, pages 87-129, then checked twice before it went up

03

Solving inequalities

k<c    c<k<candk>c    k>c or k<c|k| < c \iff -c < k < c \quad \text{and} \quad |k| > c \iff k > c \text{ or } k < -c
kk
algebraic expressiondimensionlessdimensionless
cc
positive real number constantdimensionlessdimensionless

When you use it

Use when solving linear inequalities where an expression is enclosed in absolute value bars.

Watch out

Treating a greater-than absolute value inequality as a single compound inequality instead of two separate disjoint conditions.

Drafted from Grade 9 Mathematics, pages 130-161, then checked twice before it went up

When you use it

Use when finding the solution region of a linear inequality or system of linear inequalities on the coordinate plane.

Watch out

Selecting a test point that lies directly on the boundary line fails to determine which side of the region to shade.

Drafted from Grade 9 Mathematics, pages 130-161, then checked twice before it went up

IntervalSet InequalityBoundary Dots
(a,b)(a, b)a<x<ba < x < bOpen dots at aa and bb
[a,b][a, b]axba \le x \le bSolid dots at aa and bb
(a,b](a, b]a<xba < x \le bOpen dot at aa, solid dot at bb
[a,b)[a, b)ax<ba \le x < bSolid dot at aa, open dot at bb

When you use it

Use when expressing the solution set of an inequality on a number line or in interval format.

Watch out

Using square brackets or solid dots for strict inequalities includes boundary points that are not part of the solution.

Drafted from Grade 9 Mathematics, pages 130-161, then checked twice before it went up

When you use it

Use when simplifying or solving an algebraic inequality by multiplying or dividing both sides by a negative value.

Watch out

Failing to reverse the inequality direction when multiplying or dividing by a negative number changes the solution set.

Drafted from Grade 9 Mathematics, pages 130-161, then checked twice before it went up

When you use it

Use when solving factored inequalities of the form m times n greater than 0 or m times n less than 0.

Watch out

Assuming both factors have the same sign when their product is negative. They must have opposite signs.

Drafted from Grade 9 Mathematics, pages 130-161, then checked twice before it went up

04

Introduction to trigonometry

When you use it

Check this before setting up sine, cosine, or tangent ratios for a given acute angle.

Watch out

The hypotenuse is always opposite the 90 degree angle, but opposite and adjacent sides swap places when you switch from one acute angle to the other.

Drafted from Grade 9 Mathematics, pages 162-180, then checked twice before it went up

b2+p2=h2b^2 + p^2 = h^2
hh
hypotenusemm
bb
basemm
pp
perpendicular sidemm

When you use it

Use this to find an unknown side length of a right-angled triangle or to verify if a triangle is a right-angled triangle.

Watch out

The hypotenuse h must always be the longest side opposite the 90 degree angle. Never substitute a leg in place of h.

Drafted from Grade 9 Mathematics, pages 162-180, then checked twice before it went up

sinA=oppositehypotenuse,cosA=adjacenthypotenuse,tanA=oppositeadjacent\sin A = \frac{\text{opposite}}{\text{hypotenuse}}, \quad \cos A = \frac{\text{adjacent}}{\text{hypotenuse}}, \quad \tan A = \frac{\text{opposite}}{\text{adjacent}}
AA
acute angle^\circ
opposite\text{opposite}
side opposite to angle Amm
adjacent\text{adjacent}
side adjacent to angle Amm
hypotenuse\text{hypotenuse}
hypotenusemm

When you use it

Use these ratios to relate an acute angle with the side lengths in a right-angled triangle.

Watch out

The opposite and adjacent sides depend on which acute angle is chosen. Make sure they are identified with respect to angle A.

Drafted from Grade 9 Mathematics, pages 162-180, then checked twice before it went up

Ratio$0^\circ$$30^\circ$$45^\circ$$60^\circ$$90^\circ$
sinA\sin A0012\frac{1}{2}12\frac{1}{\sqrt{2}}32\frac{\sqrt{3}}{2}11
cosA\cos A1132\frac{\sqrt{3}}{2}12\frac{1}{\sqrt{2}}12\frac{1}{2}00
tanA\tan A0013\frac{1}{\sqrt{3}}113\sqrt{3}undefined

When you use it

Use these exact values when evaluating trigonometric expressions with standard acute angles without a table.

Watch out

The value of tan 90 degrees is undefined because division by zero occurs.

Drafted from Grade 9 Mathematics, pages 162-180, then checked twice before it went up

05

Regular polygons

A=12aPA = \frac{1}{2} a P
AA
area of the regular polygonm2\text{m}^2
aa
apothem of the regular polygonm\text{m}
PP
perimeter of the regular polygonm\text{m}

When you use it

Use this formula to calculate the area of any regular polygon when its apothem and perimeter are known.

Watch out

The apothem is the perpendicular distance from the center to a side, not the radius to a vertex.

Drafted from Grade 9 Mathematics, pages 181-208, then checked twice before it went up

θ=(n2)×180n\theta = \frac{(n - 2) \times 180^\circ}{n}
θ\theta
measure of each interior angle^\circ
nn
number of sides of the regular polygon11

When you use it

Use this formula to find the measure of a single interior angle in a regular polygon where all angles are equal.

Watch out

This formula applies only to regular polygons. Irregular polygons do not have equal interior angles.

Drafted from Grade 9 Mathematics, pages 181-208, then checked twice before it went up

s=2rsin(180n)s = 2r \sin\left(\frac{180^\circ}{n}\right)
ss
side length of the regular polygonm\text{m}
rr
radius of the circumscribed circlem\text{m}
nn
number of sides of the regular polygon11

When you use it

Use this formula to calculate the side length of an n-sided regular polygon inscribed in a circle of radius r.

Watch out

Remember to multiply by 2 because the perpendicular bisector splits the full side into two equal halves.

Drafted from Grade 9 Mathematics, pages 181-208, then checked twice before it went up

06

Congruency and similarity

When you use it

Check this whenever a word problem asks how changing side lengths changes the area or perimeter.

Watch out

Multiplying side lengths by 2 doubles the perimeter, but multiplies the area by 2^2 = 4.

Drafted from Grade 9 Mathematics, pages 209-246, then checked twice before it went up

A1A2=(s1s2)2=k2\frac{A_1}{A_2} = \left(\frac{s_1}{s_2}\right)^2 = k^2
A1A_1
Area of first similar figurem2\text{m}^2
A2A_2
Area of second similar figurem2\text{m}^2
s1s_1
side length of first figurem\text{m}
s2s_2
corresponding side length of second figurem\text{m}
kk
scale factor11

When you use it

Use when finding the area of a similar plane figure given side lengths or the scale factor.

Watch out

Remember to square the scale factor. The ratio of areas is k^2 and not k.

Drafted from Grade 9 Mathematics, pages 209-246, then checked twice before it went up

P1P2=s1s2=k\frac{P_1}{P_2} = \frac{s_1}{s_2} = k
P1P_1
Perimeter of first similar figurem\text{m}
P2P_2
Perimeter of second similar figurem\text{m}
s1s_1
side length of first figurem\text{m}
s2s_2
corresponding side length of second figurem\text{m}
kk
scale factor11

When you use it

Use to find an unknown perimeter or side length when two geometric figures are similar.

Watch out

Match strictly corresponding sides in order when setting up the ratio.

Drafted from Grade 9 Mathematics, pages 209-246, then checked twice before it went up

CriterionGiven Equality or RatioConclusion
AAA=D and B=E\angle A = \angle D \text{ and } \angle B = \angle EABCDEF\triangle ABC \sim \triangle DEF
SSSABDE=BCEF=ACDF\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}ABCDEF\triangle ABC \sim \triangle DEF
SASABDE=ACDF and A=D\frac{AB}{DE} = \frac{AC}{DF} \text{ and } \angle A = \angle DABCDEF\triangle ABC \sim \triangle DEF

When you use it

Use these tests to prove two triangles are similar using minimum required angle or side conditions.

Watch out

In SAS similarity, the congruent angle must be the included angle between the two proportional sides.

Drafted from Grade 9 Mathematics, pages 209-246, then checked twice before it went up

07

Vectors in two dimentions

When you use it

When combining two non parallel vectors to find their resultant.

Watch out

Never add the magnitudes of two vectors directly using scalar addition unless they act in the exact same direction.

Drafted from Grade 9 Mathematics, pages 247-262, then checked twice before it went up

a=x2+y2|\mathbf{a}| = \sqrt{x^2 + y^2}
a|\mathbf{a}|
magnitude of vector aunits\text{units}
xx
horizontal component of vector aunits\text{units}
yy
vertical component of vector aunits\text{units}

When you use it

Use to find the length or magnitude of a two dimensional vector given in column form.

Watch out

Always square negative components to get a positive value before adding under the square root.

Drafted from Grade 9 Mathematics, pages 247-262, then checked twice before it went up

PQ=(x2x1)2+(y2y1)2|\vec{PQ}| = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
PQ|\vec{PQ}|
magnitude of vector PQunits\text{units}
x1x_1
x coordinate of initial point Punits\text{units}
y1y_1
y coordinate of initial point Punits\text{units}
x2x_2
x coordinate of terminal point Qunits\text{units}
y2y_2
y coordinate of terminal point Qunits\text{units}

When you use it

Use to calculate the magnitude of a vector between given initial and terminal points on a coordinate plane.

Watch out

Subtract the initial point coordinates from the terminal point coordinates, not the other way around, to preserve direction.

Drafted from Grade 9 Mathematics, pages 247-262, then checked twice before it went up

AB+BC=AC\vec{AB} + \vec{BC} = \vec{AC}
AB\vec{AB}
first vector from initial point A to terminal point Bunits\text{units}
BC\vec{BC}
second vector from initial point B to terminal point Cunits\text{units}
AC\vec{AC}
resultant vector connecting initial point A to terminal point Cunits\text{units}

When you use it

Use to find the resultant vector when the initial point of the second vector connects to the terminal point of the first vector.

Watch out

Ensure the tail of the second vector is placed at the head of the first vector before connecting initial to terminal.

Drafted from Grade 9 Mathematics, pages 247-262, then checked twice before it went up

08

Statistics and Probability

Mean=x1+x2++xnn\text{Mean} = \frac{x_1 + x_2 + \dots + x_n}{n}
xix_i
Individual data valuenonenone
nn
Total number of observationsnonenone

When you use it

Use when finding the average of an unorganized list of numerical values.

Watch out

Divide by the total count of values, not by the maximum value in the set.

Drafted from Grade 9 Mathematics, page 263 onwards, then checked twice before it went up

Mean=f1x1+f2x2++fkxkf1+f2++fk\text{Mean} = \frac{f_1 x_1 + f_2 x_2 + \dots + f_k x_k}{f_1 + f_2 + \dots + f_k}
xix_i
Data value or class scorenonenone
fif_i
Frequency of the corresponding data valuenonenone

When you use it

Use when calculating the mean of data given in a frequency table.

Watch out

Divide by the sum of frequencies, not by the number of rows in the table.

Drafted from Grade 9 Mathematics, page 263 onwards, then checked twice before it went up

Change to each data valueResulting Mean
Add ppMean+p\text{Mean} + p
Subtract ppMeanp\text{Mean} - p
Multiply by nonzero pppMeanp \cdot \text{Mean}
Divide by nonzero ppMeanp\frac{\text{Mean}}{p}

When you use it

Use to quickly determine the new mean when every data value is changed by the same constant operation.

Watch out

The sum of deviations of all original values from their mean is always zero.

Drafted from Grade 9 Mathematics, page 263 onwards, then checked twice before it went up

Questions students ask

What do the Grade 9 Mathematics cards cover?
33 cards across 8 chapters of the national textbook: The number system, Solving equations, Solving inequalities, Introduction to trigonometry, Regular polygons, Congruency and similarity, Vectors in two dimentions and Statistics and Probability. You can take any chapter one card at a time on the page itself.
Is there a national exam in Grade 9?
No. Ethiopia sets national exams in Grade 6, Grade 8 and Grade 12 only. These cards are for your school's own exams, and for the national exam that comes a few years later.
Where do these cards come from?
They are drafted from Grade 9 Mathematics, the Ministry of Education textbook for this grade. A second pass that cannot see the chapter then re-derives every formula, constant and table row, and anything it cannot confirm is held back instead of published.
Is this free?
Yes. Every card here is free to read and the printable sheet is free to download. Neither needs an account.
When was this last checked?
30 August 2026. Cards arrive chapter by chapter, and the line under each one says when that card was last read through.

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